American College of Education
American College of Education is a private for-profit 4-year institution in Indianapolis, IN. It enrolls about 11,961 students.
| Field | Value |
|---|---|
| Type | Private for-profit 4-year |
| Control | private for-profit |
| Level | 4-year |
| Location | Indianapolis, IN 46204 |
| County | Marion County |
| Enrollment | 11,961 |
| Acceptance rate | — |
| Applicants / admitted | — |
| In-state tuition & fees | $6,240 |
| Out-of-state tuition & fees | $6,240 |
| Graduation rate (150%) | — |
| Transfer-out rate | — |
| Campus setting | City: Large |
| Size category | 10,000 - 19,999 |
| Highest degree offered | Doctor's degree |
| Website | www.ace.edu/ |
| Phone | 8002800307 |
Admissions
This institution does not report first-year admission figures to IPEDS, often because admission is open.
Cost
Tuition and required fees are about $6,240 for full-time first-year students, the same for in-state and out-of-state students, which is typical of private institutions. Room and board are extra.
Outcomes
A 150% graduation rate is not reported for this institution in the 2023 collection — common for very small, new or specialised institutions.
Where it is
American College of Education is in Indianapolis, IN, Marion County. Its coordinates are 39.7698, -86.1602.
Nearby institutions
Frequently asked questions
What is the acceptance rate at American College of Education?
American College of Education does not report a selective admission rate to IPEDS; it may have open admission.
How much does American College of Education cost?
Tuition and required fees are about $6,240 for in-state students, excluding room and board.
How many students attend American College of Education?
About 11,961 students are enrolled.